Answer Key Upd — Lab Activity Blood Type Pedigree Mystery

allele from both biological parents. A man with Type AB blood possesses only IAcap I to the cap A-th power IBcap I to the cap B-th power alleles; he has no allele to pass on.

Any relative with Type B, Type AB, or Type O blood is excluded if the evidence is Type A. Final Identification:

The lab focuses on two distinct inheritance patterns to solve the mystery: Ear Lobe Attachment : This is an autosomal recessive

The answer key would conclude which claimants are biologically possible and which are definitely not, often revealing that the “obvious” claimant (e.g., Type AB) is impossible given the grandparents. lab activity blood type pedigree mystery answer key upd

Baby X (or Baby Y depending on the exact sub-version text, but mathematically the Smiths are the only ones who can parent an AB or an O child if both parents are heterozygous). Square Proof: IAcap I to the cap A-th power IBcap I to the cap B-th power IAIBcap I to the cap A-th power cap I to the cap B-th power IBicap I to the cap B-th power i IAicap I to the cap A-th power i Q4: Can an Rh+ parent have an Rh- child? Explain. Answer: Yes, if both parents are heterozygous carriers

Their genotype must be possible based on their parents' genes. 💡 Study Tip: The "Work Backward" Method

Aris leaned back in his chair, the mystery solved. It wasn't a story of betrayal or a clinical error. It was a masterpiece of recessive genetic camouflage. He saved the annotated pedigree file and closed his laptop, ready to deliver the news that would keep a family's history intact. allele from both biological parents

If you have your specific data table, I can help you verify the for and Rita's offspring!

They have the specific recessive trait (attached earlobes) seen by the witness.

The new key requires students to write out possible parental genotypes. For instance, if a mother is type A (genotype unknown) and a father is type B (genotype unknown), the key shows all four possible Punnett squares (A × B, A × BB, AA × B, AA × BB) before concluding that a type O child is impossible only if both parents are homozygous (AA and BB). This teaches that phenotype does not always reveal genotype—a critical lesson in genetics. Final Identification: The lab focuses on two distinct

Baby 3 (Type B) belongs to Family Brown. If the mother passes her IBcap I to the cap B-th power allele and the father passes his recessive allele, the child will be IBicap I to the cap B-th power i Summary Master Matrix Mother's Genotype Father's Genotype Assigned Baby Baby's Genotype Smith Baby 1 (Type O) Jones IAicap I to the cap A-th power i IAIAcap I to the cap A-th power cap I to the cap A-th power IAIBcap I to the cap A-th power cap I to the cap B-th power Baby 2 (Type AB) IAIBcap I to the cap A-th power cap I to the cap B-th power Brown IBicap I to the cap B-th power i IAicap I to the cap A-th power i Baby 3 (Type B) IBicap I to the cap B-th power i

The specific name from the activity is not provided here, as it can vary slightly between worksheet versions (e.g., "Mystery in Wexford," "Mystery in Hespeler"). However, the methodology to arrive at the correct answer is absolute. Your final report should include the individual's name from your worksheet, their position in the pedigree, and a clear statement that they are the culprit.

), leaving Baby Y as an impossibility for the Joneses—revealing a second secret or adoption storyline in the lab narrative. Official Answer Key Sheet Answer:

are codominant to each other, and both are completely dominant over the recessive