Design the longitudinal tension reinforcement for a continuous, multi-span reinforced concrete bridge deck at the ultimate limit state (ULS) for bending. Concrete Class: C35/45 Steel Grade: B500B Section Depth ( ): Effective Depth ( ): Step-by-Step Solution Step 1: Determine Material Strengths Calculate design compressive strength ( fcdf sub c d end-sub ) and design yield strength ( fydf sub y d end-sub
A 300mm thick retaining wall is cast against a stiff raft foundation. The wall is 15m long with no movement joints. Calculate the crack width due to early-age thermal contraction.
hc,eff=3002=150 mmh sub c comma e f f end-sub equals 300 over 2 end-fraction equals 150 mm
vRd,c=CRd,c⋅k⋅(100⋅ρl⋅fck)1/3v sub cap R d comma c end-sub equals cap C sub cap R d comma c end-sub center dot k center dot open paren 100 center dot rho sub l center dot f sub c k end-sub close paren raised to the 1 / 3 power worked examples to eurocode 2 volume 2
vmin=0.035⋅k3/2⋅fck1/2=0.035⋅(1.62)1.5⋅(25)0.5=0.360 MPav sub m i n end-sub equals 0.035 center dot k raised to the 3 / 2 power center dot f sub c k end-sub raised to the 1 / 2 power equals 0.035 center dot open paren 1.62 close paren to the 1.5 power center dot open paren 25 close paren to the 0.5 power equals 0.360 MPa Step 5: Final Evaluation
z=d2[1+1−3.53⋅K]=14502[1+1−3.53(0.074)]=1395 mmz equals d over 2 end-fraction open bracket 1 plus the square root of 1 minus 3.53 center dot cap K end-root close bracket equals 1450 over 2 end-fraction open bracket 1 plus the square root of 1 minus 3.53 open paren 0.074 close paren end-root close bracket equals 1395 mm Check stress block depth
In the context of the concrete industry, Worked Examples to Eurocode 2: Volume 2 Calculate the crack width due to early-age thermal
This example outlines the design verification for a post-tensioned, simply supported concrete bridge girder spanning 30 meters.
σs=NEdAs=320×1031340=238.8 MPasigma sub s equals the fraction with numerator cap N sub cap E d end-sub and denominator cap A sub s end-fraction equals the fraction with numerator 320 cross 10 cubed and denominator 1340 end-fraction equals 238.8 MPa Step 2: Determine Effective Concrete Area in Tension ( Ac,effcap A sub c comma e f f end-sub
This article provides a comprehensive overview of , a critical resource for structural engineers specializing in concrete design. Volume 2 provides a fully resolved STM with
Volume 2 provides a fully resolved STM with actual bar bending schedules—not just force diagrams.
"Yes," Leila said. "But there's another twist. The arch's horizontal thrust changes with live load. So we have three load cases: minimum thrust (cracking governs) and maximum thrust (serviceability stress governs)."
Volume 2 extends the fundamental principles of concrete design to structures subjected to harsh environments, dynamic loading, and complex stress distributions.
The primary goal of this write-up is to bridge the gap between theoretical code clauses and practical application. You will typically find: Detailed Design Scenarios
Authoritative guides, such as the JRC Bridge Design Examples , follow a rigid sequence to ensure code compliance: 1. Definition of Actions and Materials